It took 7.5 mL of 2.8 x 10^-3 M NaOH so that is M x L = moles HCl.
You have that many moles H^+ in the 300 mL sample of water; therefore, divide mole/L = M = concn H^+.
The total acidity in water samples can be determined by neutralization with standard sodium hydroxide solution. What is the total concentration of hydrogen ion, H+, present in a water sample if 300. mL of the sample requires 7.5 mL of 2.8 10-3 M NaOH to be neutralized?
im confused as to what i am solving for?
is it H+ ions? can someone help me with this step by step?
1 answer
1 answer