here
d = r ยท t
d = 2t (tortoise)
d + 180 = 8t (rabbit)
d = 2t
d = 8t - 180
2t = 8t - 180
Can you solve for t and answer?
the tortoise running 8.8 foot/min, the rabbit gives him 20 min and chases after with the speed 440 ft/min. how many feet the rabbit has to run to catch up?
8 answers
how did you get the numbers? 2t and 180 and 8?
ok fine here
Let x = number of minutes run by the tortoise since the hare started running
Distance = (Rate)(Time)
Distance (in feet) of tortoise since the hare started running = 180 + 2x
Distance (in feet) run by the hare in x minutes = 8x
The hare catches up to the tortoise when 8x = 180 + 2x
6x = 180
x = 30 minutes
The hare catches up to the tortoise in 30 minutes ( Half an hour).
Let x = number of minutes run by the tortoise since the hare started running
Distance = (Rate)(Time)
Distance (in feet) of tortoise since the hare started running = 180 + 2x
Distance (in feet) run by the hare in x minutes = 8x
The hare catches up to the tortoise when 8x = 180 + 2x
6x = 180
x = 30 minutes
The hare catches up to the tortoise in 30 minutes ( Half an hour).
are you sure? it seems a lot! in a half hour the rabbit would have covered 30*440 ft that is 13200 ft, while the tortoise runs 30 min (or 50 if we count the bunnys nap) 30 min*8.8 feet =264 feet (or 8.8*50 min = 440 feet)... the rabbit will be over the hill by then
OMG just trust me
look at the numbers, the rabbit cannot run for a half hour, that is waaaay to much!
The method was good, though, thank you, it showed me the way!! the rabbit will run 0.4081632 minutes or 179.59 feet when catches up! thank you!
turtle runs 8.8*20 min= 176 feet while bunny napping, so
440*x =8.8x +176
x=0.4081632 (min)
thank you again! it helped a lot
turtle runs 8.8*20 min= 176 feet while bunny napping, so
440*x =8.8x +176
x=0.4081632 (min)
thank you again! it helped a lot
your welcome, i told you to trust me
2 answers