Asked by Anna

The torques acting on the crane boom can be computed about anaxis passing through the top of the boom. (this is the place wherethe spring scale and mass hanger connect to the boom) apply thesecond condition for equilibrium to the crane boom and derivethe resulting equation for the sum of torques about this newpoint
Answered by bobpursley
What equation?
Answered by Anna
exactly. This is all I was given. Possibly

SumOf t = T(exp)*length* sin(theta) - W(hang) * length * sin(phi) - W(boom) * L(exp) * sin(phi) = 0

but im not sure.
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