The titration of HCl with NaOH is represented by the equation

Question

HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

What volume of 0.100 M HCl is required to titrate 50.0 mL of 0.500 M NaOH?

Answer 1

Any volume can titrate an acid with a base; you probably mean titrate to the equivalence point. For a 1:1 acid/base system such as NaOH/HCl you may use
mLHCl x MHCl = mLNaOH x MNaOH