The threshold wavelength for photoelectric emission in metal is 600 nm.Find the maximum kinetic energy of the electrons emitted when it is exposed to the wavelength 200 nm

Answer 1

KE of emission=energyIncident-workfunction

workfuncion=hc/600nm solve that in joules

then energy incident=hc/200nm

KE=hc(1/200-1/600)1/nm=hc/1E-9 (4 /600)=4*E-9*hc/600