The thiosulfate ion (S2O32-) is oxidized by iodine as follows:

Question

2S2O32-(aq) + I2(aq) → S4O62-(aq) + 2I-(aq)

In a certain experiment, 4.41×10-3 mol/L of S2O32- is consumed in the first 11.0 seconds of the reaction.

Calculate the rate of production of iodide ion in mol/L/s

Answer 1

4.41E-3/11 sec is rate of consumption S2O3^2-. Rate of production I^- is same.