cross section ... (π / 4)[(do)^2 - (di)^2]
volume = cross section * length
mass = volume * density
weight = m g
The thickness of a metallic tube is 1 cm and the inner diameter of the tube is 12 cm find the weight of 1 metre long tube is the density of the metal be 7.8 gram per centimetre cube
2 answers
Area of circle:
A = d² π / 4
Inner diameter:
d1= 12 cm
Outer diameter:
d2 = d1 + 2 ∙ thickness
d2 = d1 + 2 ∙ 1 = 12 + 2 = 14 cm
Area of ring:
A = ( d2² - d1² ) ∙ π / 4
A = ( 14² - 12² ) ∙ π / 4
A = ( 196 - 144 ) ∙ π / 4
A = 52 ∙ π / 4
A = 13 π cm²
1 m = 100 cm
Volume:
V = A ∙ L
V = 13 π ∙ 100
V = 1300 π cm³
ρ = density
Weight:
w = V ∙ ρ
w = 1300 π ∙ 7.8 = 1300 ∙ 3.14159 ∙ 7.8 = 31 855.7226 gr
1kg = 1000 gr
w = 31.8557226 kg
A = d² π / 4
Inner diameter:
d1= 12 cm
Outer diameter:
d2 = d1 + 2 ∙ thickness
d2 = d1 + 2 ∙ 1 = 12 + 2 = 14 cm
Area of ring:
A = ( d2² - d1² ) ∙ π / 4
A = ( 14² - 12² ) ∙ π / 4
A = ( 196 - 144 ) ∙ π / 4
A = 52 ∙ π / 4
A = 13 π cm²
1 m = 100 cm
Volume:
V = A ∙ L
V = 13 π ∙ 100
V = 1300 π cm³
ρ = density
Weight:
w = V ∙ ρ
w = 1300 π ∙ 7.8 = 1300 ∙ 3.14159 ∙ 7.8 = 31 855.7226 gr
1kg = 1000 gr
w = 31.8557226 kg