The terms 4x + 36, 2x - 6, and 3x - 27 are consecutive terms in an arithmetic sequence. What is the value of x ?

Answer 1

since the difference is constant,

(2x-6) - (4x+36) = (3x-27) - (2x-6)
now just solve for x

Answer 2

2x-6-4x-36=3x-27-2x-6
2x-4x-3x+2x=-27-6+36
-5x=3
x=-3
x=-3_5