The terminal side of an angle in standard position goes through the poin (-2,5). Find the values of the 6 trig function

Question

sin
cos
tan
csc
sec
cot

Answer 1

did you make a diagram?
you would have a right-angled triangle in the second quadrant with x=-2 and r=5
so
x^2 + y^2 = r^2
4 + y^2 = 25
y = ± √21

but we are in quadrant II, so y = +√21

now, knowing the trig rations in terms of x,y, and r, your question is easy

e.g. tan(angle) = y/x = - √21/2
sec(angle) = r/x = - 5/2

you do the rest.