The tension in a 2.8-m-long, 1.2-cm-diameter steel cable (ρ = 7800 kg/m3) is 825 N. What is the fundamental frequency of vibration of the cable?

Answer 1

Fundamental wavelength = 5.6 m
V = Wave speed = sqrt(T/(ñ*A))
T = tension = 825 N
A = pi*d^2/4 = cross sectional area of cable
d = 0.012 m
Solve for V. Then use
Fundamental frequency
= V/(Fund. Wavelength)

Answer 2

thanks! but whats ñ

Answer 3

That was supposed to be your density symbol, rho. I never know what Greekm (or Spanish) symbols are going to pop up when I cut and paste.

Answer 4

thanks! may I ask how you calculate the fundamental wavelength or is it a constant?

Answer 5

calculated**