To solve this problem, we can use the inverse variation formula:
T1 * V1 = T2 * V2
Where:
T1 = initial temperature
V1 = initial volume
T2 = final temperature
V2 = final volume
Given:
T1 = 25°C
V1 = 90 cm^3
V2 = 20 cm^3 (compressed volume)
Substitute these values into the formula:
25 * 90 = T2 * 20
Solve for T2:
2250 = 20T2
T2 = 112.5°C
Therefore, the temperature of the gas will be 112.5°C when it is compressed to a volume of 20cm^3.
The temperature T of a given mass of gas varies inversely with its volume V. The temperature of 90cm^3of a certain gas is 25°C. What will the temperature of the gas be when it is compressed to a volume of 20cm^3?
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