integral of T dt from t = 0 to t = 256
divided by 256
[ 20 t + (5.25/1.75) t^1.75 ] at 256 - at 0 divided by 256
at 0 it is 0
[ 20(256) + 3 (256^1.75) ] / 256
20 + 3 (256)^.75
= 20 + 3(64)
= 212 interesting, boiling point of water
The temperature of a chemical reaction,
t
seconds after the reaction starts, is given
by:
T(t)= 20+5.25t^.75 degrees F
,
What is the average temperature during the whole process, if the reaction lasts for 4
minutes and 16 seconds ?
3 answers
Thanks! I get why you did every thing in the numerator but why did you have to divide by 256?
oh is it because it is the average?