The temperature of 4.60 mol of an ideal monatomic gas is raised 15.0 K in an adiabatic process. What are (a) the work W done by the gas, (b) the energy transferred as heat Q, (c) the change ΔEint in internal energy of the gas, and (d) the change ΔK in the average kinetic energy per atom?

Answer 1

Since no heat is added, you must be increasing the temperature by isentropic compression. Negative work is done BY the gas.

For (a) Calculate the P dV integral using the fact that
Po*Vo^(5/3) = P*V^(5/3)

Work = integral P dV =
Po*Vo^(5/3)* integral of dV/V^(5/3)

More information is required about the initial conditions of the gas. Does it start out at S.T.P. ?

Answer 2

(b) Since this is an adiabatic process, the heat transferred in or out is zero. That is the definition of adiabatic.