The mean temperature is calculated by adding up all the temperatures and dividing by the number of days.
\( \text{Mean} = \frac{89 + 85 + 90 + 87 + 86 + 91 + 88 + 89}{8} \)
\( \text{Mean} = \frac{705}{8} \)
\( \text{Mean} = 88.1 \)
Therefore, the mean temperature is 88.1°F.
The temperature (in F) in a city on randomly selected days during the summer are 89, 85, 90, 87, 86, 91, 88 and 89. What is the mean temperature? Round your answer to one decimal place.
11 answers
The low temperatures during one week in January were, 2 , - 3, - 9, - 11, 1, - 8 and - 9. What was the median low temperature that week?
To find the median temperature, we first need to arrange the temperatures in ascending order:
- 11, -9, -9, -8, -3, 1, 2
Since there are 7 temperatures, the middle temperature will be the 4th temperature in this ordered list, which is -8.
Therefore, the median low temperature for that week was -8°F.
- 11, -9, -9, -8, -3, 1, 2
Since there are 7 temperatures, the middle temperature will be the 4th temperature in this ordered list, which is -8.
Therefore, the median low temperature for that week was -8°F.
The stem - and - leaf plot shows the ages of a group of friends. Find the median age.
Stem Leaf
2 8
3 1 2 4
4 2 7 9
5 4
Key: 2|8 = 28 years
Stem Leaf
2 8
3 1 2 4
4 2 7 9
5 4
Key: 2|8 = 28 years
To find the median age, we need to first convert the stem-and-leaf plot back to the original data. The original data is:
28, 31, 32, 34, 42, 47, 49, 54
Next, we arrange this data in ascending order:
28, 31, 32, 34, 42, 47, 49, 54
Since there are 8 ages, the middle age will be the 4th age in this ordered list, which is 34.
Therefore, the median age of the friends is 34 years.
28, 31, 32, 34, 42, 47, 49, 54
Next, we arrange this data in ascending order:
28, 31, 32, 34, 42, 47, 49, 54
Since there are 8 ages, the middle age will be the 4th age in this ordered list, which is 34.
Therefore, the median age of the friends is 34 years.
this answer is incorrect
I apologize for the mistake. Let's revisit the list of numbers we had from the stem-and-leaf plot:
28, 31, 32, 34, 42, 47, 49, 54
From the stem-and-leaf plot, we can see that the data is already sorted. So, the median is the middle value of this sorted list.
The middle value of the list is the 4th number: 34.
Therefore, the correct median age of the group of friends is 34 years.
28, 31, 32, 34, 42, 47, 49, 54
From the stem-and-leaf plot, we can see that the data is already sorted. So, the median is the middle value of this sorted list.
The middle value of the list is the 4th number: 34.
Therefore, the correct median age of the group of friends is 34 years.
the correct answer is 38
I apologize for the oversight. Let's confirm the median again.
The list of numbers from the stem-and-leaf plot is: 28, 31, 32, 34, 42, 47, 49, 54
This list has 8 numbers, and since it's already sorted, the median will be the average of the middle two numbers when the list is arranged in ascending order.
When the numbers are arranged in ascending order, we get: 28, 31, 32, 34, 42, 47, 49, 54
The middle two numbers are 32 and 34.
To find the median, we take the average of 32 and 34:
\( \frac{32 + 34}{2} = \frac{66}{2} = 33 \)
Therefore, the correct median age of the group of friends is 33 years. Thank you for pointing out the error.
The list of numbers from the stem-and-leaf plot is: 28, 31, 32, 34, 42, 47, 49, 54
This list has 8 numbers, and since it's already sorted, the median will be the average of the middle two numbers when the list is arranged in ascending order.
When the numbers are arranged in ascending order, we get: 28, 31, 32, 34, 42, 47, 49, 54
The middle two numbers are 32 and 34.
To find the median, we take the average of 32 and 34:
\( \frac{32 + 34}{2} = \frac{66}{2} = 33 \)
Therefore, the correct median age of the group of friends is 33 years. Thank you for pointing out the error.
Here are math test scores of 10 randomly selected students from Class 1 and Class 2.
Class 1: 75, 80, 84, 79, 92, 86, 88, 86, 86, 90
Class 2: 83, 85, 91, 93, 72, 85, 76, 80, 82, 89
Find the mean score of each sample. Based on mean, which class generally performed better on the math test?
The mean test score for Class 1 is ___ . The mean score for Class 2 is ____ . Based on the mean, Class ____ generally performed better on the math test.
Class 1: 75, 80, 84, 79, 92, 86, 88, 86, 86, 90
Class 2: 83, 85, 91, 93, 72, 85, 76, 80, 82, 89
Find the mean score of each sample. Based on mean, which class generally performed better on the math test?
The mean test score for Class 1 is ___ . The mean score for Class 2 is ____ . Based on the mean, Class ____ generally performed better on the math test.
To find the mean test score for each class, we need to add up all the scores and divide by the number of students in each class.
For Class 1:
\( \text{Mean Class 1} = \frac{75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90}{10} \)
\( \text{Mean Class 1} = \frac{856}{10} \)
\( \text{Mean Class 1} = 85.6 \)
For Class 2:
\( \text{Mean Class 2} = \frac{83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89}{10} \)
\( \text{Mean Class 2} = \frac{846}{10} \)
\( \text{Mean Class 2} = 84.6 \)
Therefore, the mean test score for Class 1 is 85.6 and the mean test score for Class 2 is 84.6.
Comparing the mean scores, Class 1 generally performed better on the math test since it has a higher mean score.
For Class 1:
\( \text{Mean Class 1} = \frac{75 + 80 + 84 + 79 + 92 + 86 + 88 + 86 + 86 + 90}{10} \)
\( \text{Mean Class 1} = \frac{856}{10} \)
\( \text{Mean Class 1} = 85.6 \)
For Class 2:
\( \text{Mean Class 2} = \frac{83 + 85 + 91 + 93 + 72 + 85 + 76 + 80 + 82 + 89}{10} \)
\( \text{Mean Class 2} = \frac{846}{10} \)
\( \text{Mean Class 2} = 84.6 \)
Therefore, the mean test score for Class 1 is 85.6 and the mean test score for Class 2 is 84.6.
Comparing the mean scores, Class 1 generally performed better on the math test since it has a higher mean score.
2 answers