The taxi fare in a city is such that rs.50 is the fixed amount for the first two kilometers and rs.10 for the subsequent kilometers is charged.Taking the distance covered as " x"km and total fare as rs ." Y" ,write a linear equation in "x" and "y" .Represent it graphically

2 answers

y =
0.50 for x <= 2
0.50 + 0.10(x-2) for x > 2

technically, it is a step function, so
y = 0.50 + 0.10⌈x-1⌉ for x > 2
sorry. that's ⌈x-2⌉