The table shows the motion data for two objects during two trials of an investigation.



Motion Investigation Data
Object Number Trial Number Distance Traveled (meters) Time (seconds)
Object 1 1 400 20
2 600 30
Object 2 1 55 11
2 45 9


Which object travels at the greater average speed?
1.Object 2, because it travels the shorter amount of time

2.Object 1, because it travels the greater distance per unit of time

3.Object 2, because it travels the shorter distance per unit of time

4.Object 1, because it travels the longer amount of time

1 answer

2. Object 1, because it travels the greater distance per unit of time

To calculate average speed, you divide the total distance traveled by the total time taken. Object 1 travels a total distance of 1000 meters in 50 seconds (400 + 600 = 1000 meters, 20 + 30 = 50 seconds), giving it an average speed of 20 meters per second. Object 2 travels a total distance of 100 meters in 20 seconds (55 + 45 = 100 meters, 11 + 9 = 20 seconds), giving it an average speed of 5 meters per second. Therefore, Object 1 travels at a greater average speed.
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