The survival rate during a risky operation for patients with no other hope of survival is 87%. What is the probability that exactly four of the next five patients survive this operation? (Give your answer correct to three decimal places.)

I got 3.48

4 answers

Incorrect
p(s) =0.87
n = 5

P(x =4)
P(x) = nCx p^x(1-p)^n-x

(5C4)(0.87)^4(0.13)^1 = 0.372
Thank you, I left out a complete step is how I missed it...
Sorry for the different names, there is a group of us trying to work these out together and using one computer when we have questions...
No problem