the surface areas of two similar solids are 340 yd2 and 1158 yd2 the volume of the larger solids is 1712 yd3 what is the volume of the smaller solid?

Answer 1

the surface area of two similar objects is proportioal to the square of their sides
the volume of two similar objects is proportional to the cube of their sides

so ratio of sides of smaller : larger = √340 : √1158
so volume smaller/volume of larger = (√340)^3 / (√1158)^3
volume of smaller = 1712(√340)^3 / (√1158)^3
= appr 272.37 yds^3