The surface area of a cube is given by the formula 6s^2, where s is the length of one side of the cube.
Let's say the length of one side of the larger cube is s1 and the length of one side of the smaller cube is s2.
So, the surface area of the larger cube is 6s1^2 and the surface area of the smaller cube is 6s2^2.
To find how many times the surface area of the smaller cube is in the surface area of the larger cube, we divide the surface area of the larger cube by the surface area of the smaller cube.
Therefore, the surface area of the larger cube is (6s1^2) / (6s2^2) = s1^2 / s2^2 times the surface area of the smaller cube.
the surface area of the larger cube is how many times the surface area of a smaller cube
3 answers
what about 10 and 20
If the length of one side of the larger cube is 20 units and the length of one side of the smaller cube is 10 units, we can calculate the surface area of each cube.
Surface area of the larger cube = 6 * (20)^2 = 6 * 400 = 2400 square units
Surface area of the smaller cube = 6 * (10)^2 = 6 * 100 = 600 square units
To find out how many times the surface area of the smaller cube is in the surface area of the larger cube:
2400 (surface area of larger cube) / 600 (surface area of smaller cube) = 4
Therefore, the surface area of the larger cube is 4 times the surface area of the smaller cube.
Surface area of the larger cube = 6 * (20)^2 = 6 * 400 = 2400 square units
Surface area of the smaller cube = 6 * (10)^2 = 6 * 100 = 600 square units
To find out how many times the surface area of the smaller cube is in the surface area of the larger cube:
2400 (surface area of larger cube) / 600 (surface area of smaller cube) = 4
Therefore, the surface area of the larger cube is 4 times the surface area of the smaller cube.