The acceleration to the center of the galaxy is a = V^2/R
R = 2.55*10^20 m
V = (2*pi*R)/[(250*10^6)*365*24*3600]
= 2.03*10^5 m/s
a = 1.6*10^-10 m/s^2. Pretty small
The sun goes around the center of our galaxy once every 250 million years. The sun is also 2.55×10^20 m from the center of our galaxy. What is the acceleration of our sun towards the center of the galaxy in m/s^2?
Details and assumptions
You may assume the sun's orbit is circular.There are 24 hours in a day and 365 days in a year.
1 answer