the sumof three positive numbers is 26.the second number is 3times as large as the first.if te sum of the squares of these numbers is least find the numbers

Answer 1

x+y+z = 26
y = 3x

You want minimal x^2+y^2+z^2, so check out a few possibilities:

x y z ∑*^2
1 3 22 488
2 6 18 332
3 9 14 208
...

I think you can figure it out.

Answer 2

that sucks