x^2+x-210=0
(x-14)(x+15) = 0
The sum of two numbers is 210. If one number is the square of the other, find the set of numbers.
Thanks
3 answers
Thanks Steve.
One number x.
So, the other number: 210 – x.
According to the given condition,
x^2 = 210 – x,
ox^2 + x – 210 = 0,
or (x + 15) (x – 14) = 0,
or x = –15 or 14.
Therefore, one number is either –15 or 14 and the other number is either (210 + 15) = 225 or (210 – 14) = 196.
So, the other number: 210 – x.
According to the given condition,
x^2 = 210 – x,
ox^2 + x – 210 = 0,
or (x + 15) (x – 14) = 0,
or x = –15 or 14.
Therefore, one number is either –15 or 14 and the other number is either (210 + 15) = 225 or (210 – 14) = 196.