The sum of two numbers is 15. Four times the smaller number is 60 less than twice the larger number. What is the larger number?

Answer 1

4s = 2L - 60

s = (2L-60)/4

s + L = (2L-60)/4 + L = 15

Solve for L.

Answer 2

s + L = 15 ... s = 15 - L

4 s + 60 = 2 L

substituting ... 60 - 4 L + 60 = 2 L

solve for L

Answer 3

x = larger
15 - x = smaller

Four times the smaller number is 60 less than twice the larger number.

4(15 – x) = 2x - 60
60 - x = 2x - 60
Solve for x

Answer 4

is "Anonymous" so named because the response is incorrect?