the sum of two numbers exceeds their product by one. their differences is equal to their product less five . find the two numbers

17 answers

let n-1st no.
m-2nd no.
n+m=(nXm)+1-----eqtn. 1
n-m=(nXm)-5-----eqtn. 2

solve by elimination

n+m=(nXm)+1-----eqtn. 1
-
n-m=(nXm)-5-----eqtn. 2
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2m=6

m=3
subst. to eqtn 1 or 2

n+m=(nXm)+1-----eqtn. 1
n+3=3n+1
-2n=-2
n=1

therefore, the nos. are 3 and 1

True and thank you for the answer

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true and thanks for the answer

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correct

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Yes

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