a = first number
b = second number
Conditions:
a + b = 39
2 a + 3 b = 101
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a + b = 39 Subtract b to both sides
a + b - b = 39 - b
a = 39 - b
2 a = 2 ( 39 - b )
2 a = 78 - 2 b
2 a + 3 b = 101
78 - 2 b + 3 b = 101
78 + b = 101 Subtract 78 to both sides
78 + b - 78 = 101 - 78
b = 23
a = 39 - b
a = 39 - 23
a = 16
First number = 16
Second number = 23
the sum of two number is 39 . twice the first number plus 3 times the second numberis 101. find the numbers.
x+x+1=39
2x=38
x=19
twice the first number 19 it would be 38 and 57 b three times the second number. i know is wrong kind o but please tell me.
3 answers
The sum of 2 numbers is 78. Three times the first number less five times the second number is -22. What are the numbers?
Bow can you figure this answer out with put using formulas