The sum of two integers is -4. Their difference is 12. Name the integers.

Answer 1

x+Y=-4 EQ1
x-y=12 EQ2

x=y+12 EQ3

put in the first equation
x+y=-4
substitute equation 3 for x
y+ (y+12)=-4
2y+12=-4
2y= -4-12
2y =-16
y= -16/2
y= -8

Put the new value of y in EQ3
x= y+12
x= -8+12
x= 4

so two numbers are 4 and -8