x+y+z = 7
y = 2z+1
x+z = y-2
x+y+z = 7
x-y+z = -2
2y = 9
y = 9/2
z = 7/4
x = 3/4
The sum of three whole numbers is 7. The second number is 1 more than the twice of the third number. The
sum of first and third number is 3 less than the second number. Find all the three numbers. Thanks
1 answer