The sum of three numbers is 132.

Question

The third number is 4 times the second.
The first number is 6 more than the second.
What are the numbers?

Answer 1

Let's call the second number "x."

According to the problem, the first number is 6 more than the second, so it must be:

x + 6

The third number is 4 times the second, so it must be:

4x

We know that the sum of all three numbers is 132, so we can set up the equation:

(x + 6) + x + 4x = 132

Now we just need to solve for x:

6x + 6 = 132

Subtract 6 from both sides:

6x = 126

Divide both sides by 6:

x = 21

So the second number is 21.

Now we can use this information to find the first and third numbers:

First number: x + 6 = 27

Third number: 4x = 84

Therefore, the three numbers are 27, 21, and 84.