the sum of three integers is 220. The sum of the first and second integers exceeds the third by 94. The third integer is 55 less than the first. Find the three integers.

Answer 1

first ---- x
third ---- x-55
second ---- 220 - (x + x - 55) = 275- 2x

"The sum of the first and second integers exceeds the third by 94"
---> x + x-55 = 275-2x + 94
4x = 424
x = 106

first is 106
third is 51
second is 63

check:
sum = 106+51+63 = 220 , ok
1st + 2nd = 157
3rd = 63
is 157 > 63 by 94 ? YES