Let's represent the smallest odd integer as x.
Since there are consecutive odd integers, the second odd integer would be x + 2 and the third odd integer would be x + 4.
The sum of these three odd integers can be represented as:
x + (x + 2) + (x + 4) = 39
Simplifying the equation, we get:
3x + 6 = 39
Subtracting 6 from both sides, we have:
3x = 33
Dividing both sides by 3, we get:
x = 11
Therefore, the smallest odd integer is 11.
The sum of three consecutive odd intergers is 39. What is the smallest of these intergers?
1 answer