The sum of three consecutive numbers is 72. What is the largest of these numbers? (1 point)

23
25
26
28

1 answer

Let's call the smallest number x. The next consecutive number would be x + 1, and the one after that would be x + 2.
According to the problem, the sum of these three numbers is 72. So, we can set up the equation:
x + (x + 1) + (x + 2) = 72
3x + 3 = 72
Subtracting 3 from both sides gives:
3x = 69
Dividing both sides by 3 gives:
x = 23
Therefore, the largest of the three numbers is x + 2 = 23 + 2 = 25.
The answer is 25.