The sum of three consecutive numbers is 57. What is the largest of these numbers?

(1 point)

Group of answer choices

19

21

20

18

1 answer

Let's call the first number x.

Then the three consecutive numbers would be x, x+1, and x+2.

According to the problem, the sum of these three numbers is 57.

So, we can write the equation as:

x + (x+1) + (x+2) = 57

Simplifying the equation, we have:

3x + 3 = 57

Subtracting 3 from both sides, we get:

3x = 54

Dividing both sides by 3, we find:

x = 18

Therefore, the largest of these three numbers is x+2, which is 18 + 2 = 20.

So, the answer is 20.