The sum of third and seventh term of an ascending arithmetic progression is 12 and their product is 32.

Then find the ninth term?

1 answer

c'mon, guy - use what you know abot APs:

(a+2d)+(a+6d) = 12
(a+2d)(a+6d) = 32

Now just solve for a and d, then you want a+8d.

Hint: 4*8 = 32