Fist number= a
Second number= a+1
Third number= a+2
a^2+(a+1)^2+(a+2)^2=194
(a+1)^2=a^2+2*a*1+1^2=a^2+2a+1
(a+2)^2=a^2*2a*2+2^2=a^2+4a+4
a^2+a^2+2a+1+a^2+4a+4=194
3a^2+6a+1+4=194
3a^2+6a+5-194=0
3a^2+6a-189=0
The exactsolutions of this equation are:
a=7 and a=-9
Solution:
First number 7
Second number 7+1=8
Third number 7+2=9
7^2+8^2+9^2=49+64+81=194
The sum of the squares of three consecutive integers is 194. what are the integers?
3 answers
how did u get a to b 7 and 9
In google type:
"quadratic equation online"
When you see list of result click on:
webgraphingcom/quadraticequation_quadraticformula.jsp
When this page be open in rectacangle type equation:
3a^2+6a-189=0
and click option solve it!
You will see solutions of this equation Step-by-step
"quadratic equation online"
When you see list of result click on:
webgraphingcom/quadraticequation_quadraticformula.jsp
When this page be open in rectacangle type equation:
3a^2+6a-189=0
and click option solve it!
You will see solutions of this equation Step-by-step