a+d + a+5d = 4
2a + 6d = 4
a+3d= 2
a+2d - (a+10d) = 24
a+2d-a-10d=24
-8d=24
d = -3
into a+3d = 2 ---> a - 9 = 2
a = 11
the first 3 terms are
11, 8, 5
..........................
check:
11 8 5 2 -1 -4 -7 -10 -13 - 16 - 19
2nd + sixth = 8 + (-4) = 4, that checks
third term = 5
11th term = -19 , difference = 24
all looks good
The sum of the second ans the sixth terms of an arithmetic sequence is 4.Thw third term is 24 more than the 11th term.
1Determine the first three terms in the sequence.
1 answer
1 answer