1/x + 1/(x + 2) = 9/40
To clear the denominators, we multiply everything by 40x(x + 2), giving:
40(x + 2) + 40x = 9x(x + 2)
Expanding both sides, we get:
40x + 80 + 40x = 9x^2 + 18x
80x + 80 = 9x^2 + 18x
Rearranging the terms, we get a quadratic equation:
9x^2 - 62x - 80 = 0
We can factor this quadratic equation to solve for x:
(9x + 10)(x - 8) = 0
Setting each factor to zero:
9x + 10 = 0 or x - 8 = 0
x = -10/9 or x = 8
Since the integers are consecutive even numbers, we need to choose the positive value of x:
x = 8
So the two consecutive even integers are 8 and 10.
The sum of the reciprocals of two consecutive even integers is 9/40. This can be represented by the equation shown.
1/x+1/x+2=9/40
Use the rational equation to determine the integers. Show all work.
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