The sum of the length, width, and height of a box is 80 cm. The length is 10 cm less than twice the sum of the width and the height, and twice the width exceeds the height by 6 cm. Find the height of the box.

Answer 1

If the dimensions are x,y,z then we have

x+y+z = 80
x = 2(y+z)-10
2y = z+6

Now just solve for z.