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The sum of the first n terms os the series is given Sn=2n(n+3). Show that the terms of the series forms an arithmetic progression.

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2n(n+3) = (4n)/2 (2*8 + ((4n)-1)*4)
So, if m = 4n,
Sm = m/2 (2*8 + (m-1)*4)

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