It says "the number is twelve more than one hundred times the hundred digit"
The number is 100z+10y+x. So, you want
100z+10y+x = 100z+12
Now plug in your values and solve for x.
the sum of the digits of a three digit number is six. the ten digit is one less than the units digit and the number is twelve more than one hundred times the hundred digit
Find the three digits
x
y=x-1
z=7-2x
x+x-1+z=6
2x-1+z=6
z=7-2x
x-1=100(7-2x)+12
what is wrong with my reasoning?
1 answer
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