h + t + u = 6
h = 2 u
t = h + u ... 2 t = 6 ... t = 3
h + u = 3 ... 3 u = 3 ... u = 1
h + 3 + 1 = 6 ... h = 2
The sum of the digits of a three-digit number is 6. The hundreds digit is twice the units digit, and the tens digit equals to the sum of the other two. Find the number.
1 answer