the sum of the digit of a two digit number is 13 and the diffrence btween the number and that form by reversing the digit is 27, find the number...

1 answer

in the original number let the unit digit by x and the tens digit be y
the number is 10y+x
x+y = 13

then the number reversed is 10x + y

10x + y - (10y + x) = 27
9x - 9y = 27
x-y = 3

add the two equations:
2x = 16
x = 8
then y = 13-8 = 5

the number is 58

check:
85-58 = 27 ,
all is good