a + 3d + a + 7d = 10
2a + 10d = 10
a + 5d = 5
a+5d + a+11d = 22
2a + 16d = 22
a + 8d = 11
subtract them
3d = 6
d = 2
back into the first
a + 5d = 5
a + 10 = 5
a = -5
first 3 terms are -5, -3, -1
the sum of the 4th and 8th terms is 10, and the sum of the 6th and 12th terms is 22. Find the first three terms.
1 answer