n^3 - (n-2)^3 = 6 n^2 + ....
so, A = 1/6.
The sum of odd squares can be expressed as
1^2+3^2+5^2+…+(2n-1)^2=An^3+Bn^2+Cn+D.
The value of A can be expressed as a/b, where a and b are positive co-prime integers. What is the value of a+b?
1 answer