180(n-2) = 1080
n-2 = 6
n = 8
So the polygon has 8 sides and 8 vertices.
Each of the 8 vertices can form a triangle with 2 of the other 7 vertices.
8*6 = 48 triangles can be formed.
But some have been counted twice. How many?
google can provide some insights.
The sum of interior angles of a regular polygon is 1080 degrees .What is the number of triangles the polygon can subdivide into
2 answers
(2n-4)90, when n=6
1080=(2*6-4)90
1080=8*90
1080/72=
1080=(2*6-4)90
1080=8*90
1080/72=