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The sum of four numbers in arithmetic progression is 16. The square of the last number is the square of the first number plus 48. What are the four numbers?

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A+A+d+A+2d+a+3d=16
4A+6d=16
2A+3d=8

(A+3d)^2=A^2+48

second equation...
A^2+6dA+9d^2=a^2+48
3d(2A+3d)=48
3d*8=48
d=2
then 2A+6=8
A=1

1,3,5,7

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