The sum of four consecutive integers is at least 114. Find the smallest possible values for these numbers.

Question

HOW YOU DO THIS?

Answer 1

Let x = first integer
Then x + 2 = next integer
x + 4 = third integer
x + 6 = fourth consecutive integer

x + x + 2 + x + 4 + x + 6 > 114

4x + 12 > 114

4x > 102

Answer 2

thanks

Answer 3

so the first number would be 25.50
then 2nd would be 27.50

Answer 4

Ray -- that can't be right. The directions state that these are EVEN numbers.

Answer 5

is that correct

Answer 6

i don't get tell me please

Answer 7

102 / 4 = 25.5

The nearest even number is 26. That must be the

Check it out: 26 + 28 + 30 + 32 = ?

Aren't these the smallest possible values for these numbers?

Answer 8

yea you had to round

Answer 9

But look consecutive numbers are Numbers which follow each other in order, without gaps, from smallest to largest.

12, 13, 14 and 15 are consecutive numbers.

THEY ARE NOT EVEN

Answer 10

IT SHOULD BE WITHOUT GAPS

Answer 11

I'm sorry. I thought they were supposed to be even numbers. I apologize.

You're right, there should be no gaps.

Answer 12

Let's start again. (I think I've read the problem correctly this time.)

x + x + 1 + x + 2 + x + 3 > 114

4x + 6 > 114

4x > 108

x = 27

Check: 27 + 28 + 29 + 30 = 114

Answer 13

thank you

Answer 14

You're welcome.

And again -- I'm sorry I steered you wrong.

The few times I taught math, I offered my students extra credit whenever they saw that I'd made a stupid mistake like this.