x+y = 19
(x+5)(y+5) = 208
now just solve for x and y.
The sum of ages of two sisters are 19 years.in five years time the product of their ages will be 208.what are their ages?
4 answers
older sister --- x
younger sister --- 19-x
in 5 years:
(x+5)(24-x) = 208
-x^2 + 19x + 120 - 208 = 0
x^2 - 19x + 88 = 0
(x-11)(x-8) = 0
x = 11 or x = 8
older sis is 11, younger is 8
check:
in 5 years:
16(13) = 208 , all is good
younger sister --- 19-x
in 5 years:
(x+5)(24-x) = 208
-x^2 + 19x + 120 - 208 = 0
x^2 - 19x + 88 = 0
(x-11)(x-8) = 0
x = 11 or x = 8
older sis is 11, younger is 8
check:
in 5 years:
16(13) = 208 , all is good
11 and 8
Correct