x^2 + x < 12
x^2 + x - 12 < 0
(x+4)(x-3) < 0
Now, you know that this is a parabola, and since it opens upward, it is negative between the roots. So,
-4 < x < 3
Since you specified non-negative,
0 < x < 3
the sum of a non-negative number and its square is less than 12.what could the number be?
1 answer
1 answer