Let's assume that the first number in the sequence is x.
Since the numbers are consecutive even numbers, the second number would be x + 2, the third number would be x + 4, and the fourth number would be x + 6.
According to the problem, the sum of these numbers is 36. So, we can write this equation:
x + (x + 2) + (x + 4) + (x + 6) = 36
Simplifying this equation, we get:
4x + 12 = 36
Subtracting 12 from both sides, we get:
4x = 24
Dividing both sides by 4, we get:
x = 6
Therefore, the first number in this sequence is 6.
The sum of 4 consecutive even numbers is 36
What is the first number in this sequence?
1 answer