The sum of 3 consecutive odd natural numbers is 69. Find the prime number out of these numbers.

Answer 1

let the 3 consecutive odds be
n, n+2, and n+4

n+n+2+n+4=69
3n = 63
n = 21

They are 21, 23, and 25, with 23 as the prime one

Answer 2

let the 3 consecutive no be
x,x+2,x+4

x+x+2+x+4=69
3x+6=69
3x=69-6
x=63/3
x=21

The three consecutive no are 21,23,25

Answer 3

Let the numberbe x
First number x
Second number x+2
Third number x+4
A.T.Q
X+x+2+x+4=69
3x+6=69
3X=69-6
3X=63
X=63/3
X=21

So three numbers are
21
21+2=23
21+4=25

So,23is the prime number

Answer 4

Let the first no. be =x
Let the second no. be =x+2
Let the third no. be =x+4

x + x+2 + x+4 = 69
3x + 6 = 69
3x = 69 - 6
3x = 63
x = 63/3
x = 21

First no. = 21
Second no. = 23
Third no. =25

Therefore, 23 is a prime
number

Answer 5

Astha Singh

Answer 6

Let the first no. be =x
Let the second no. be =x+2
Let the third no. be =x+4

x + x+2 + x+4 = 69
3x + 6 = 69
3x = 69 - 6
3x = 63
x = 63/3
x = 21

First no. = 21
Second no. = 23
Third no. =25

Therefore, 23 is a prime
number